Write a program that will count the number of digits in an
input integer up to value MAX_VALUE (2147483647). Thus, for
an input of 5837 the output should be
4 digits
Make sure that your program works for the numbers 0, 1, and
10. For the number 0, the output should be
1 digit
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Answer Posted / sandeep mannarakkal
I have another suggestion for the above,
int iInputNumber;// This number is used for collecting input from user.
int nCount = 1;
while ( iInputNumber /10 )
{
iInputNumber = iInputNumber/10;
nCount ++;
}
cout << nCount << endl; // nCount will have the count of digits.
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how can i access a direct (absolute, not the offset) memory
address?
here is what i tried:
wrote a program that ask's for an address from the user,
creates a FAR pointer to that adress and shows it. then the
user can increment/decrement the value in that address by
pressing p(inc+) and m(dec-).
NOW, i compiled that program and opened it twice (in 2
different windows) and gave twice the same address to it.
now look what happen - if i change the value in
one "window" of the program, it DOES NOT change in the
other! even if they point to the same address in the memory!
here is the code snippet:
//------------------------------------------------------
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