Answer Posted / er.k.pratabchandran

BLOCK SIZE :390*190*190MM(ON MUSCAT)

WITHOUT C.M NOOFBLOCK IS=1/(0.39*0.19*0.19)=71NOS

WITH C.M NOOFBLOCKS IS=1/(0.40*0.20*0.20)=62.5NOS

C.M=(71-62.5)=8.5NOS*(0.39*0.19*0.19)=0.119CUM

REQUIREMENT FOR C.M1:5=1/5*1440=288KG=5.76BAGS/CUM

FOR 0.119CUM=5.76*0.119=0.68BAGS(WITHOUT WASTAGE)

FOR SAND C.M=1/5*1.57(FACTOR FOR FINESAND)=0.314CUM

FOR 0.119CUM=0.314*0.119=0.037CUM=1.30CFT(0.037*35.315=1.30CFT)

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