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How to find out the number of records in a file using JCL
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Answer Posted / srinivasa gudla
Using Syncsort,
//SORT1 EXEC PGM=SORT
//SYSOUT DD SYSOUT=*
//SORTIN DD DSN=Input.File,DISP=SHR
//SORTOUT DD DSN=Output.File,...
//SYSIN DD *
SORT FIELDS=COPY
OUTFIL FILES=OUT,TRAILER1=
(1:COUNT),REMOVECC,NODETAIL
/*
This job creates a report with a single trailer record
containing the record count.
The COUNT subparameter of TRAILER1 provides the number of
records for the entire report (all the records) starting at
position 1.
REMOVECC omits the ANSI carriage control character from all
of the report records.
NODETAIL generates a report with no data records, only
header and trailer records, as specified.
| Is This Answer Correct ? | 4 Yes | 3 No |
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