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i have a file which contains records like
10,30,90,50,20,40,80,60,70
i want to display these records in reverse order like
70,60,80,40,20,50,90,30,10
please give me the cobol code (do not sort the records)
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Answer Posted / ch.ranveer singh gurjar
you can try its give you 100% exact output...
above solution for file its for no
NOTE:USE RIGHT JCL AND RIGHT FORMAT INPUT AND OUTPUT FILE
by
CH. RANVEER SINGH GURJAR(ACS A XEROX)
IDENTIFICATION DIVISION.
PROGRAM-ID. 'OCCURS'.
ENVIRONMENT DIVISION.
INPUT-OUTPUT SECTION.
FILE-CONTROL.
SELECT INFILE ASSIGN TO DD1.
SELECT OUTFILE ASSIGN TO DD2.
DATA DIVISION.
FILE SECTION.
FD INFILE.
01 INREC.
05 IN-NUM PIC X(2).
05 FILLER PIC X(78).
FD OUTFILE.
01 OUTREC.
05 OUT-NUM PIC X(2).
05 FILLER PIC X(78).
WORKING-STORAGE SECTION.
01 WS-COUNT PIC 9(4).
01 EOF PIC X(1) VALUE 'N'.
01 ARRAY1.
05 ARREC OCCURS 1 TO 50 TIMES DEPENDING ON WS-COUNT.
10 AR-NUM PIC X(5).
PROCEDURE DIVISION.
MOVE 1 TO WS-COUNT.
OPEN INPUT INFILE.
OPEN OUTPUT OUTFILE.
PERFORM MOVE-RECORD UNTIL EOF = 'Y'.
PERFORM PARA1 UNTIL WS-COUNT = ZEROS
CLOSE INFILE.
CLOSE OUTFILE.
STOP RUN.
MOVE-RECORD.
READ INFILE AT END MOVE 'Y' TO EOF
NOT AT END
MOVE INREC TO ARREC(WS-COUNT)
DISPLAY WS-COUNT
ADD 1 TO WS-COUNT.
PARA1.
MOVE ARREC(WS-COUNT) TO OUTREC
WRITE OUTREC
SUBTRACT 1 FROM WS-COUNT.
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