You have one employee table having 3 entries emp_id, Mgr_id
and salary. Mgr_id is also referencing emp_id. so now find
out the emp_id which are having the second highest salary,
under a particular manager.
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Answer Posted / rajesh
select * from (select
emp_id,mgr_id,salary,dense_rank()over(partition by mgr_id order by salary desc nulls last) rn from emp) where rn=2;
| Is This Answer Correct ? | 5 Yes | 1 No |
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