Answer Posted / ak

It's simple.
Since in question it is asked how to call "non virtual
function in derived class" which means in derived class we
need to access non-virtual function using Base Class's pointer.

Note:
In question its no where mentioned that we cannot use
virtual function in Base class.


So in Base class same function can be made virtual and we
can use it through Base's pointer.



See eg. below:


class Base
{
public:
virtual void fun()
{
cout<<"Inside Base's fun";
}

};


class Derived : public Base
{
public:
void fun()
{
cout<<"Inside Derived's fun";
}


};



int main()
{

Base *bp = new Derived;
bp->fun();



getch();
}

Whats is abstraction in oops?

1070

---

Is abstract thinking intelligence?

1046

---

What is balance factor?

1075

---

hi, this is raju,iam studying b.tech 2nd year,iam want know about group1 and group2 details, and we can studying without going to any instutions? please help me.

1947

---

What is difference between data abstraction and encapsulation?

1076

---

What is the purpose of polymorphism?

1122

---

There are two base class B1,B2 and there is one class D which is derived from both classes, Explain the flow of calling constructors and destructors when an object of derived class is instantiated.

1988

---

This program numbers the lines found in a text file. Write a program that reads text from a file and outputs each line preceded by a line number. Print the line number right-adjusted in a field of 3 spaces. Follow the line number with a colon, then one space, then the text of the line. You should get a character at a time and write code to ignore leading blanks on each line. You may assume that the lines are short enough to fit within a line on the screen. Otherwise, allow default printer or screen output behavior if the line is too long (i.e., wrap or truncate). A somewhat harder version determines the number of spaces needed in the field for the line numbers by counting lines before processing the lines of the file. This version of the program should insert a new line after the last complete word that will fit within a 72-character line.

2114

---

What is polymorphism in oop example?

1018

---

What is pointer in oop?

1043

---

Where is pseudocode used?

1095

---

What is a function in oop?

1077

---

What is the advantage of oop over procedural language?

1078

---

What are the benefits of interface?

1051

---

#include #include #include #include void insert(struct btreenode **, int); void inorder(struct btreenode *); struct btreenode { struct btreenode *leftchild; struct btreenode *rightchild; int data; }; main() { struct btreenode *bt; bt=(struct btreenode *)NULL; int req,i=1,num; clrscr(); printf("Enter number of nodes"); scanf("%d",&req); while(i<=req) { printf("Enter element"); scanf("%d",&num); insert(&bt,num); i++; } inorder(bt); } void insert(struct btreenode **sr, int num) { if(*sr==NULL) { *sr=(struct btreenode *)malloc (sizeof(struct btreenode)); (*sr)->leftchild=(struct btreenode *)NULL; (*sr)->rightchild=(struct btreenode *)NULL; (*sr)->data=num; return; } else { if(num < (*sr)->data) insert(&(*sr)->leftchild,num); else insert(&(*sr)->rightchild,num); } return; } void inorder(struct btreenode *sr) { if(sr!=(struct btreenode *)NULL) { inorder(sr->leftchild); printf("\n %d",sr->data); inorder(sr->rightchild); } else return; } please Modify the given program and add two methods for post order and pre order traversals.

3752

---