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If a car starts from A towards B with some velocity due to
some problem in the engine after travelling 30km.If the car
goes with 4/5 th of its actuval velocity the car reaches B
45min later to the actual time. If the car engine fails
ofter travelling 45km, the car reaches the destination B
36min late to the actual time , what is the initial
velocity of car and what is the distance between A and B in km
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Answer Posted / namrata gupta
Let the distance between A and B is x and the velocity initially is v
then according to the given conditions
[30/v]+[(x-30)/(4v/5)] = [x/v]+3/4 here 3/4 is for 45 minute
[45/v]+[(x-45)/(4v/5)] = [x/v]+3/5 here 3/5 is for 36 minute
on solving we will get (x-30)/v = 3 and (x-45)/v = 12/5
or x-30 = 3v and x-45 = 12v/5 or x = 105 and v = 25
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