Answer Posted / vinaymb

Consider an example

#include "stdio.h"
main ()
{
char *ptr = "BANGLAORE";
*ptr = "b";
}

This Program will compile without any error. But on running
this program you will get the Segmentation error. Because
the ptr will hold the address which is read-only and we are
changing the value at the read-only which will result in
segmentation fault.

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