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A starts from a place at 11.00 am and travels at a speed of
4 kmph , B starts at 1.00 pm and travels with speeds of 1
kmph for 1 hr , 2 kmph for the next hr , 3 kmph for the
next hr and so on. At wht time will B catch up with A ?
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Answer Posted / avinash
They will meet after 1 pm.A has unique speed 4 km/hr.so,A cross 8 km at 1 pm.But,B increase speed like(1+2+3+4+5+6+7+8+9 = 45).For A 9*4=36 + 8=44. so before 9 pm and after 8:30 pm they should meet.So, Answer is : 8:45 PM.
| Is This Answer Correct ? | 1 Yes | 3 No |
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