There are 8 stones which are similar except one which is
heavier than the others. To find it, you are given a pan
balance. What is the minimal number of weighing needed to
find out the heaviest stone ?
Answer Posted / siddhartha
@Monu, even if 9 stones are there, only two weighings are
required...
In general, in n weighings, you can determine the heavier
stone out of 3^n stones...
If 9 stones are there...
3---3---3
weigh the first two... if one is heavy, take that group,
else take the third group of three...
In this group of three thus taken, weigh any two. If any of
them if heavy, that is the stone.
Else the remaining one stone is the heavier one... :)
Is This Answer Correct ? | 2 Yes | 0 No |
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