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a dog takes 4 leaps for every 5 leaps of a hare but 3
leaps of a dog are equal to 4 leaps of the hare .compare
their speeds(.......... please give explanation....)
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Answer Posted / diffraction
let us assume
speed of dog D speed of hare H
leap of dog X leap of hare Y
now
a dog takes 4 leaps for every 5 leaps of a hare
let time T
in time T
dog =4X/D=T hare=5Y/H=T
3 leaps of a dog are equal to 4 leaps of the hare
3Y=4X
so
3Y/D=5Y/H=T
so D/H=3/5
| Is This Answer Correct ? | 7 Yes | 17 No |
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