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What is the smallest whole number that, when divided by 2,
leaves a remainder of 1; when divided by 3, leaves a
remainder of 2; and so on, up to leaving a remainder of 9
when divided by 10?
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Answer Posted / sudhanshu_kmr
According to the question when the number is divided by 2,3,..10 leaves remainder 1,2,...9 respectively. It means that if we increase the that number by 1 then it is divisible by each of the numbers 2,3,..10.
So, find a number that is common divisor of 2,3,4,...and 10.
And subtract 1 from it.
LCM of 2,3,..10 is 2520.
2520-1 = 2519
thus, 2519 is the required number.......
| Is This Answer Correct ? | 11 Yes | 2 No |
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