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can we declare s9(9)v9(9) in cobol ? if yes how many bytes
it will occupy ?(urgent plz answer it)
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Answer Posted / rajagopal
For the above question the answer is 19.Because sign is
allocated automatically and in cobol user defined value
should not exceed 18.so it'll take 19bytes including sign
without giving any error.but if you give
s9(9).9(9),definitely it'll give error because it's user
defined length is 19 and with sign it'll take 20 bytes and
it'll definitely throw an error.Anyway if you give
parm.cobol=arith(extend) in compile JCL both the above cases
will work.
| Is This Answer Correct ? | 6 Yes | 5 No |
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