Answer Posted / raja

(2x - 1) (2x - 3) (2x - 5) (2x - 7) = 9
Let 2x - 4 = y
=> (y + 3) (y + 1) (y - 1) (y - 3) = 9
=> (y^2 - 1) (y^2 - 9) = 9
=> y^4 - 10y^2 + 9 = 9
=> y^2 (y^2 - 10) = 0
=> y = 0 or ± √(10)
=> 2x - 4 = ± √(10)
=> x = (1/2) [4 ± √(10)]
=> product of the irrational roots
= (1/2)^2 * [4 + √(10)] [4 - √(10)]
= (1/4) * 6
= 3/2.

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