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maths answer key of cgl tier II exam held on 1 august 2010
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Answer Posted / prem prakash gupta
There was one question which many candidates have mistaken to understand :-
The sum of all the digits of the numbers from 1 to 100.
(A) 5050
(B) 903
(C) 901
(D) 900
Correct Ans. (C) 901
Many candidates have understood this question as to find the sum of numbers from 1 to 100 but they haven't noticed that the question is asking to find the sum of the "DIGITS" of the numbers from 1 to 100.
so when we count the digits 1 to 9, that how many times they are repeated in the numbers from 1 to 100....we find that 1 is repeated 21 times and the rest 2 to 9 are repeated 20 times each.Hence the correct answer will be :-
(21*1)+20(2+3+4+5+6+7+8+9)=21+20*44=21+880=901.
| Is This Answer Correct ? | 6 Yes | 2 No |
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