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How will the following value be internally allocated
'18787'
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Answer Posted / sheeba
hey acording to me...its 4 bytes.... if we convert the
above value to binary format dats how it stores rite
so...2power4(1
)+2p3(8)+2p2(7)+2p1(8)+2p0(7)=131....so 3 bytes...and 1
unused... totally 4 bytes......
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