can we declare s9(9)v9(9) in cobol ? if yes how many bytes
it will occupy ?(urgent plz answer it)
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Answer Posted / y@$w@nth
s9(9)v9(9)
Here v stands for assumed decimal point so it will occupy
only 18 bytes(9+9)...if instead of s9(9)v9(9) it is coded as
s9(9).9(9) then it is going to occupy 19 bytes ((9+9)+1)
the extra 1 byte for decimal point .........There is no way
of occupying 20 bytes storage.
| Is This Answer Correct ? | 47 Yes | 5 No |
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