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If a car starts from A towards B with some velocity due to
some problem in the engine after travelling 30km.If the car
goes with 4/5 th of its actuval velocity the car reaches B
45min later to the actual time. If the car engine fails
ofter travelling 45km, the car reaches the destination B
36min late to the actual time , what is the initial
velocity of car and what is the distance between A and B in km
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Answer Posted / ravi ranjan sinha
let x is distance from A to B
and y is initial speed.
30/y+(x-30)5/4y -x/y = 3/4
=>
4x-12y=120 ----(1).
45/y + (x-45)5/4y -x/y=3/5
=>
5x-12y=225 -------(2).
From equ (1) and equ (2) we will get.
x=25 and y=105
so initial speed is 25
and Distance From A to B is 105
Ans 25,105
| Is This Answer Correct ? | 32 Yes | 11 No |
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