Answer Posted / alpesh patel

Normality of Con. HCl =(Purity of Hcl * 10 * specific
gravity of HCl)/ Eq. wt. of HCl

Where 10 is multiplied to convert in normal soln.(1000 mL)

= (36 * 10 * 1.18)/36.5 = 11.64 N.(N1)

Now,N1V1 = N2V2

v1 = (1 * 1000)/11.64
= 85.9 mL

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