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why we are taking 85 ml of concentrated HCl to prepare 1N
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Answer Posted / alpesh patel
Normality of Con. HCl =(Purity of Hcl * 10 * specific
gravity of HCl)/ Eq. wt. of HCl
Where 10 is multiplied to convert in normal soln.(1000 mL)
= (36 * 10 * 1.18)/36.5 = 11.64 N.(N1)
Now,N1V1 = N2V2
v1 = (1 * 1000)/11.64
= 85.9 mL
| Is This Answer Correct ? | 88 Yes | 14 No |
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