Answer Posted / karthik

Another way:
let t = students who passed one or both subjects,
and x = total students

n(e U h) = n(e) + n(h) - n(e intersection h)
=> x = 0.8t + 0.7t - 144
=> x = 1.5t - 144
=>1.5t - x = 144 --------(1)

students who failed both subjects is 10%
=>x-t = 0.1x
=>0.9x - t = ---------(2)

Solving (1) & (2), we get x = 240.

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