Answer Posted / hemant gor

Two Methods, First from Calculation, 2nd using SP16
1st Method Compute K= Mu/(fcu x b x d^2)
for Fy = 415 if K<= 0.138 Singly Reinforced

Calculate Z/d = 0.5 + sqrt { 0.25 - K/0.865}

Area of Steel = Mu / { 0.87 x fy x Z }
Z is Lever Arm Distance Between CG of Tension and Compression Force

2nd Method
Calculate Mu /{b x d^2}
Check Table 2 to 5 of SP16 based on Concrete Grade
It gives Percentage of Steel Pt for given Grade of Concrete,steel and Mu/{bxd^2}

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