Answer Posted / tapojit roy

#include<stdio.h>
#include<conio.h>
void main()
{
int n,m,x,sum=0;
clrscr();
printf ("the armstrong no. from 0 to 500 are\n");
for (n=1;n<=500;n++){
m=n;
while (m>0)
{
x=m%10;
sum=sum+(x*x*x);
m=m/10;
}
if (sum==n)
{
printf("%d\n",n);
}
sum=0;
}
getch();
}

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