Answer Posted / uma mahesh

127.179(app)


given distance of the train along the wind is 695
and againt the wind is 498

and time = distance/speed

as we know that time is equal in both the cases hence equate

695/s1=498/s2-----------(1);

where s1=speed of the plane + speed of the wind
and s2=speed of the plane -speed of the wind


given that speed of the wind is 21k/h

s1=sp+21
s2=sp-21

substitu in eq 1

we get the answer as 27.17(app)

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