Answer Posted / saravanan s

See Meenakshi,It is depends on the Requirement,

So the Conclusion is

Take a look on the table

COMP COMP-3
(in bytes) (in bytes)

S9(01) 2 1
S9(02) 2 2
S9(03) 2 2
S9(04) 2 3
S9(05) 4 3
S9(06) 4 4
S9(07) 4 4
S9(08) 4 5
S9(09) 4 5
S9(10) 8 6
S9(11) 8 6
S9(12) 8 7
S9(13) 8 7
S9(14) 8 8

like that.........

Cheers,
Saravanan

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