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Question { 34081 }

#include
void main()
{
int i=1;
printf("%d%d%d",i++,++i,i);
}


Answer

ans is 2 2 1.printf gets exe from rit to left so i =1,++i is 2,den i++ is 2 ..values are pushed into stack frm rit to left..so in stack 1 gets pushed first den 2 den 2.while pop d result is 2 2 1.

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