how we do lcm of two no using c simple if while or for
statement
Answer / aditya goel
#include<stdio.h>
#include<conio.h>
main()
{
int lcm=1,a,b,c,d,x;
clrscr():
printf("Enter any two numbers:\n");
scanf("%d %d",&a,&b);
c=a;d=b;
x=(a<b)?a:b;
for(i=2;i<=x;i++)
{
if ((a%i==0) && (b%i==0))
{
lcm=lcm*i;c=c/i;d=d/i;
}
else if (a%i==0)
{
lcm=lcm*i;c=c/i
}
else if (b%i==0)
{
lcm=lcm*i;d=d/i;
}
}
lcm=lcm*c*d;
printf("lcm is %d",lcm);
getch();
}
Is This Answer Correct ? | 3 Yes | 13 No |
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