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Q#1: An algorithm is made up of 2 modules M1 and M2.If
order of M1 is F(n) and order of M2 is g (n) then what is
the order of the algorithm.
Q # 2 : How many binary trees are possible with 3 nodes?
with 4 nodes?
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Answer / sriram
iam sorry i had given the wrong answer above....
its O(f(n)*g(n)) or O(max(f(n),g(n))
2^n -n so its 5 and 12 nodes respectively.....
| Is This Answer Correct ? | 34 Yes | 3 No |
Answer / mousumi
no of binary trees possible with n nodes is 2^n-n
3->2^3-3=5 nodes
4->2^4-4=12 nodes
| Is This Answer Correct ? | 2 Yes | 4 No |
Answer / sriram
order of the algorithm is f(n)+g(n)
no of binary trees possible with n nodes is 2^n-n
3->2^3-3=5 nodes
4->2^4-4=12 nodes
| Is This Answer Correct ? | 4 Yes | 15 No |
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