what is unreachable code problem in multiple catch statements
- 3 Answers
- 5281 Views
- I also Faced
- E-Mail Answers
Answers were Sorted based on User's Feedback
Answer / deepthi
if v just gve a default exception block,bfre the specific
catch statement it ll create a unreachable code exception
e.g
catch(Exception e)
{System.out.println(unknown exception);}
catch(ArithmeticException e)
{System.out.println("Division by zero");}
| Is This Answer Correct ? | 6 Yes | 0 No |
Answer / sriragv
Subclass exception handler should come first then the
superclass has to come next. Then only code wil compile
otherwise subclass exception will be never reached results
compilation error.
| Is This Answer Correct ? | 5 Yes | 0 No |
Answer / bijoy baby
super class can handle sub class Exception. That's why when
super class handler placed before sub class handler then the
exception object will not thrown to sub class handler.
| Is This Answer Correct ? | 1 Yes | 0 No |
Can you use abstract and final both with a method?
What is an immutable class?
Is passing by reference faster?
Why do we need hashset in java?
What are thread priorities and importance of thread priorities in java?
Why does java doesnot support multiple inheritance?
What is difference between Eclips and MyEclips?
What is a nested structure?
What is core java used for?
What is the driver class?
What are the different types of sorting in java?
What is the requirement of thread in java?
Core Java 
