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What is the broadcast address of the subnet
address172.16.8.159\25?(choose from following)
172.16.99.255
172.16.127.255
172.16.255.255
172.16.64.127
172.16.64.260
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Answer / dubaskis
172.16.8.159 \ 25
172 16 8 159
10101100.00010000.00001000.10011111
8 +8 +8 +1 =25
11111111.11111111.11111111.10000000
Zeros mean, that you can change address bit, so
159=10011111 and last combination of 0011111 is changeable,
so max number in you network usually is broadcast address.
so last byte is 1(unchangeable)1111111(max sequence of
changeable bits).
11111111(bin) means 255(dec)
Whole address 10101100.00010000.00001000.11111111 =
172.16.8.255
| Is This Answer Correct ? | 14 Yes | 2 No |
Answer / kais
a class /8
b /16
c /24
/25
8 bits ( 128).64.32.16.8.4.2.1 )
got 1 bit 128
subnets 255.255.255.128
broadcast for 172.16.8.159\25 is
172.16.8.255
| Is This Answer Correct ? | 11 Yes | 3 No |
Answer / vinay
172.16.8.159 \ 25
172 16 8 159
10101100.00010000.00001000.10011111
8 +8 +8 +1 =25
11111111.11111111.11111111.10000000
Zeros mean, that you can change address bit, so
159=10011111 and last combination of 0011111 is changeable,
so max number in you network usually is broadcast address.
so last byte is 1(unchangeable)1111111(max sequence of
changeable bits).
11111111(bin) means 255(dec)
Whole address 10101100.00010000.00001000.11111111 =
172.16.8.255
1 . 172.16.99.255
2 . 172.16.127.255
3 . 172.16.255.255
| Is This Answer Correct ? | 0 Yes | 2 No |
Answer / bhanu
172.16.255.255 coz 172.16.8.159\25 = 255.255.255.128
Bhanu Pathak
HCl
| Is This Answer Correct ? | 3 Yes | 10 No |
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