solve this is my problem byte a=40,byte b=50 both add value is 90 this is with in range of byte... byte range is -128to 127.... why this pgm gives error like type mismatch.... package javapgms; public class byte1 { public static void main(String args[]) { byte a=40,b=50; byte c=a+b; System.out.println(c); } } note : dont use int k... a,b,c are in byte range... mind it..

2 Answers  

---

What is mean by UML? what is the use? where we are using?

1 Answers   Eka Software,

---

different between exception and error? explaim check and uncheck exception

4 Answers  

---

What is the use of coding?

0 Answers  

---

How many arguments can a method have java?

0 Answers  

---

what is mean by thread lock?

2 Answers   Infosys, TCS,

---

What is the difference between static (class) method and instance method?

0 Answers  

---

java Technical questions asked by JPMC

0 Answers   JPMorgan Chase,

---

What is static binding and where it occurs?

4 Answers  

---

How can we create objects if we make the constructor private ?

0 Answers  

---

Can variables be used in java without initialization?

0 Answers  

---

What is the purpose of the finalize() method?

0 Answers  

---