1apple=5rs 20grapes=1rs 1banana=1rs no. Of fruits should be 100 and cost should be 100 how?
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cost of 1 apple =5 rupees
cost of 19 apples = 95 rupees.
cost of one banana = 1 rupees
cost of 20 grapes = 1 rupees.
cost of 80 grapes = 4 rupees
therefore, total items = 100
cost of all these items = 100 rupees.
| Is This Answer Correct ? | 19 Yes | 8 No |
Answer / jagadish
for i in range(0,20):
for j in range(0,5):
for k in range(0,100):
if i+j*20+k == 5*i + j +k==100:
print ("apples-{},grapes-{},banana-{}".format(i,j*20,k))
apples-19,grapes-80,banana-1
| Is This Answer Correct ? | 1 Yes | 2 No |
DIRECTIONS for Questions 3 and 4: Answer the questions on the basis of the information given below. In an examination, there are 100 questions divided into three groups A, B and C such that each group contains at least one question. Each question in group A carries 1 mark, each question in group B carries 2 marks and each question in group C carries 3 marks. It is known that the questions in group A together carry at least 60% of the total marks. DIRECTIONS for Questions 3 and 4: Answer the questions on the basis of the information given below. In an examination, there are 100 questions divided into three groups A, B and C such that each group contains at least one question. Each question in group A carries 1 mark, each question in group B carries 2 marks and each question in group C carries 3 marks. It is known that the questions in group A together carry at least 60% of the total marks. If group B contains 23 questions, then how many questions are there in group C?
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