i have a table with the columns below as
Emp_ID Address_ID Address_Line City Country
-------- --------- ----------- ------ ---------
Q: Display the Emp_ID's those having more than one
Address_ID
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Answer / gyana ranjan behera
simply write the sql query like
sql>select Emp_ID from table_name groupe by Address_ID
having count(Address_ID )>1;
this is working as per the requirement..i tested
that..thanx ..pls send responces and questions on my mail
id to discuss new situations.
| Is This Answer Correct ? | 14 Yes | 3 No |
Answer / shashi
select Emp_ID from table_name groupe by Emp_ID
having count(Address_ID )>1;
| Is This Answer Correct ? | 3 Yes | 0 No |
Answer / ajit
Try with this its working
SELECT name,addres FROM ADDR WHERE name IN
(SELECT name FROM ADDR
GROUP BY name
HAVING COUNT(ADDRES) >1)
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / nithya
select Emp_ID from table_name group by Address_ID
having count(Address_ID )>1;
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / vijayakumar
we need some sample data's ... then only we can able to write exact query....becoz here emp_id and address_id both are unique.. same data will not repeated....
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / abc
select emp_id from table_name a where a.rowid < (select MAX
(rowid) from test b where b.address_id=a.address_id)
| Is This Answer Correct ? | 0 Yes | 1 No |
Answer / nitin
SELECT EMP_ID FROM EMP_ADDRESS WHERE ADDRESS_ID IN
(SELECT ADDRESS_ID FROM EMP_ADDRESS
GROUP BY ADDRESS_ID
HAVING COUNT(ADDRESS_ID) >1)
| Is This Answer Correct ? | 1 Yes | 3 No |
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