Answer / jaya.vavilala

output is error.because we cannot inrease address of
array.if we increase address can be increased after go on
increasing after 5th position it cannot find where it is
present.so we cannot increase array directly through
pointer we can increase.

Answer / vikas thakur

The answer is error.
The reason is that we can't increment a constant(the
variable int a[] ). The expression int a[] is the address
where the system had placed your array and it will remain
to stay at that address until the program terminates. you
can't increment an address but you can increment a pointer.

.....the correct program would be....

void main()(
int a[]={1,2,3,4,5},i;
for(i=0;i<5;i++)
printf("%d",a[i]);
getch();
}

....in another way.....

void main()(
int a[]={1,2,3,4,5},i;
int *p;
p = a;
for(i=0;i<5;i++)
printf("%d",*(p++));
getch();
}

Answer / chhaya

Here , in program array is given of 5 element. But at d
time of printing output ,increase address not pointer
i.e.
a[i]={1,2,3,4,5}
then u wnat to print array
Printf("%d",i++);
getch();

this sentence is requird. because array is set of element
and element is pointed by "pointer". If u wnt to show
element then use pointer not address of array.....

What does volatile do?

0 Answers  

---

Write a c code segment using a for loop that calculates and prints the sum of the even integers from 2 to 30, inclusive?

4 Answers  

---

what is software?

7 Answers   Wipro,

---

Define a structure to store roll no, name and marks of a student. Using the structure of above write a ‘C’ program to create a file “student.dat”. There must be one record for every student in the file. Accept the data from the user.

0 Answers  

---

I have a function which accepts a pointer to an int. How can I pass a constant like 5 to it?

3 Answers  

---

How does struct work in c?

0 Answers  

---

what is the purpose of the code, and is there any problem with it. unsigned int v[10]; unsigned int i = 0; while (i < 10) v[i] = i++;

2 Answers   Google,

---

What is the result main() { char c=-64; int i=-32 unsigned int u =-16; if(c>i){ printf("pass1,"); if(c<u) printf("pass2"); else printf("Fail2");} else printf("Fail1); if(i<u) printf("pass2"); else printf("Fail2") } a)Pass1,Pass2 b)Pass1,Fail2 c)Fail1,Pass2 d)Fail1,Fail2 e)none

9 Answers   IBM,

---

What header files do I need in order to define the standard library functions I use?

0 Answers  

---

How can I avoid the abort, retry, fail messages?

0 Answers  

---

plz answer.. a program that takes a string e.g. "345" and returns integer 345

4 Answers  

---

program for following output using for loop? 1 2 2 3 3 3 4 4 4 4 5 5 5 5 5

8 Answers   Aptech, Infosys,

---