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# define x=1+4;
main()
{
int x;
printf("%d%d",x/2,x/4);
}
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Answer / karthik
the preprocessor directive is not written correctly
so u r going to get CE
#define x 1+4
void main()
{
printf("%d%d",x/2,x/4);
}
will work fine and give output as 32
| Is This Answer Correct ? | 4 Yes | 2 No |
Answer / rama krishna sidhartha
The preprocessor syntax is wrongly written. It should be as
follows :
#define x 1+4
void main()
{
printf("%d%d",x/2,x/4);
}
There is no need of declaring the variable 'x' in
between 'main()' function since it is already declared
in '#define' directive.
The output will be : 3 and 2
| Is This Answer Correct ? | 2 Yes | 0 No |
Answer / banavathvishnu
x/2 will become 1+4/2=3
x/4 will become 1+4/4 = 2
| Is This Answer Correct ? | 3 Yes | 2 No |
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