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Schwing Stetter Interview Questions
Questions Answers Views Company eMail

what is different the DOL Starter and Star Delta STARTER

12 92213

is earthing is necessary if we use armoured cable

1 5749

Give an example of a time when you had to explain some new procedures to your co-workers for quality service delivery. How did you go about it?

3165

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Un-Answered Questions

What is the significance of the .dex files? in Android?

995


What are the advantages of using xml?

824


What will be your approach if a particular script in Load Test fails?

2260


Hi, I am new in oracle(SQL), could anyone help me in writing a correct SQL. Below is the table structure. Table: Subsc Fields: 1. Sub_no (this field will hold values of subscriber nos, for e.g. S111111, S222222, S333333, S444444, etc.) 2. s_status (this field will hold values for different status of subscriber, for e.g. 'A', 'S', 'C', etc.) 3. cus_id (this field will hold values of bill nos for e.g. 11111111, 22222222, 33333333, 44444444, etc.) Table: Bill Fields: 1. Bill_no this field will hold values of bill nos for e.g. 11111111, 22222222, 33333333, 44444444, etc.) 2. b_status = (this field will hold values for different status of bill for e.g. 'O', 'C', 'S', etc.) Note: 1. The Sub_no is a Primary key of Subsc table. 2. The cus_id is a foreign in Subsc table (referred from Bill_no field of Bill table) 3. The Bill_no field is the Primary key of Bill table. Query A --> I wrote a query to select cus_id/Bill_no which is in status open (b_status = 'O') and having more than two active subscriber (i.e. S_status = 'A') in it ( i.e. more the two subscribers in same bill). select s.cus_id from subsc s where exists (select 1 from bill where bill_no = s.cus_id and b_status = 'O') and s_status = 'A' group by s.cus_id having count(sub_no) = 2 Problem : The above query will give the cus_id (or rather bill_no) which are in open status (b_status ='O) and which are having TWO ACTIVE Subscribers (s_status ='A') in it. However, this query will also lists the cus_id/bill_no which are having more than TWO subscribers in it (but only two subscriber will be in Active status (s_status = 'A') and the others will be in s_status = 'C' or s_status = 'S'. Help needed: I want to write a query which will fetch ONLY the cus_id/bill_no which are in open status (b_status ='O') and which are having ONLY TWO ACTIVE subscribers (s_status ='A') in it. B--> If I include the sub_no in the above query then NO row are returned. select s.cus_id, s.sub_no from subsc s where exists (select 1 from bill where bill_no = s.cus_id and b_status = 'O') and s_status = 'A' group by s.cus_id, s.sub_no having count(sub_no) = 2 Help needed: I want to modify the above query which will fetch ONLY the cus_id/bill_no which are in open status (b_status ='O') and which are having ONLY TWO ACTIVE subscribers (s_status ='A') in it ALONG with the sub_no. Thanks a lot in advance. Regards, Nitin

2329


What exactly is cardiovascular disease, and what are the risk factors?

921


What is the difference between VBScript and JavaScript?

2690


Explain the dipole moment direction for methanol?

1102


What is location of log files for apache server?

1081


Explain about thinhtime and thicktime function?

665


Paano po ba nabubuo ang eclipse?

2136


Explain what are the various isolation levels possible?

1029


I have a reference table called 1. of 2 fields called 1.BadgeGroups(BG)and 1.Badges(B)like BG G aa 10 aa 11 bb 12 bb 13 bb 14 Using MS Design View Table 2 has 3 fields called 2.name, 2.badgegroup and 2.group In Table 2 called 2. they calls Table 1 for 2 fields BUT with the second field 2.badges, I want the combo box only to display the 1.badges where 2.badgegroup = 1.badgegroup The current select I have is for Table Data View Row Source is: 2.badgegroup is filled from a Combo box using Select Distinct etc from Table 1. Tried different syntax's but still lost, looking for some help SELECT 1.[BadgeGroup], 1.Badge FROM 1. WHERE 1.[BadgeGroup]=Me.2.BadgeGroup); I can populate 2.badgegroup with a

2308


Define peak time.

1122


Explain how does tcp try to avoid network meltdown?

1069


what is the process to find that one consultant had removed a table from sap tables

2528