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i am confused about generator. i have generator of 380 KVA that is 304 KW by that formula KW=KVA*0.8... then by this formula I=KW/V*1.732*0.8 the amperes are 528.673. so that is the load which i put on one phase of generator or this is total 3 phase load on Generator.......
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A 400 V, 50 Hz, Δ connected synchronous generator has a field reactance of 0.1 Ω and armature resistance of 0.015 Ω. At full load, the machine supplies 1200 A at 0.8 pf lagging. Under full-load conditions, the friction and windage losses are 40 KW and the core losses are 30 KW. What is the machine’s overall efficiency? Ignore any field circuit losses.
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