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What will be printed as the result of the operation below:
#include<..>
int x;
int modifyvalue()
{
return(x+=10);
}
int changevalue(int x)
{
return(x+=1);
}
void main()
{
int x=10;
x++;
changevalue(x);
x++;
modifyvalue();
printf("First output:%d\n",x);
x++;
changevalue(x);
printf("Second output:%d\n",x);
modifyvalue();
printf("Third output:%d\n",x);
}
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Answer Posted / selloorhari
The Output will be:
First output : 12
Second output : 13
Third output : 14
for changevalue() function:
Even though the value of x(11) is sent to
changevalue() and it returns x(12), no variable is assigned
to capture that 12. So, in main() function, x remains as 11(
not as 12 ) . then it gets incremented and prints the value
12...
And, the Same story for other functions also.....
| Is This Answer Correct ? | 2 Yes | 16 No |
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