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main()
{
char as[] = "\\0\0";
int i = 0;
do{
switch( as[i++]) {case '\\' : printf("A");
break;
case 0 : printf("B");
break;
default : printf("C");
break;
}}
while(i<3);
}
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Answer Posted / lakshman
ABC is correct answer, because in first condition switch(0)=\ then it prints the character "A" ,then its break. in next condition switch(1)=0 then its prints the character "B" . In final condition switch(2)= ,it does not match any case value so default condition is executed that means character "C" will print, so the final answer is ABC
| Is This Answer Correct ? | 2 Yes | 5 No |
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