Answer Posted / br rijal

Solution/ BR Rijal

Volume of dry concrete = 1.54 to 1.57 times volume of wet concrete
so,
calculation for 1 cu.m of concrete works:-
summation of ratio of concrete M25(1:1:2) = (1+1+2) = 4
Shrinkage Factor = 1.55 ( Assumed)
so,
Total volume of wet concrete required = 1.55 cu.m
Now,
Volume of cement required = (1/4)* 1.55 = 0.388 cu.m
= (0.388 / 1440) = 558 kg
cement required = (558 / 50) = 11.16 bags
volume of sand required = (1/4) * 1.55 = 0.388 cu.m
volume of Aggregate required = (2/4) * 1.55 = 0.775 cu.m

Therefore, For 1 cu.m of M25(1:1:2) concrete works;
cement required = 11.16 bags
sand required = 0.388 cu.m
Aggregate required = 0.775 cu.m

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