Question 50 - An aqueous solution with 2.5 g of a protein dissolved in 600 cubic centimeters of a solution at 20 degree Celsius was placed in a container that has a water-permeable membrane. Water permeated through the membrane until the h - level of the solution was 0.9 cm above the pure water. (a) Calculate the absolute temperature of the solution, T in Kelvin, where T (Kelvin) = T (degree Celsius) + 273.15. (b) Calculate the osmotic pressure, P of the solution by using the formula P = hrg where h is level of the solution, r is density of water with 1000 kg per cubic meter, g = 9.81 N / kg as gravitational acceleration. (c) Calculate the concentration of the protein solution, C in kg / cubic meter. (d) Calculate the molecular weight of the protein, (MW) = CRT / P where R = 8.314 Pa cubic meter / (mol K) as ideal gas constant.
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Answer Posted / kang chuen tat (malaysia - pen
Answer 50 - (a) T = 20 + 273.15 = 293.15 K. (b) P = hrg = (0.9 / 100) (1000) (9.81) = 88.29 Pa. (c) C = (2.5 / 1000) / (600 / 1000000) = 4.167 kg / cubic meter. (d) (MW) = CRT / P = (4.167) (8.314) (293.15) / 88.29 = 115.03 kg / mol = 115030 g / mol. The answer is given by Kang Chuen Tat; PO Box 6263, Dandenong, Victoria VIC 3175, Australia; SMS +61405421706; chuentat@hotmail.com; http://kangchuentat.wordpress.com.
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