byte a=5;
byte b=5;
byte c=a+b;
System.out.println(c);
whats the o/p?
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Answer Posted / dinesh kumar
compilation fails
possibl;e loss of precision, because
ie type mismatch error from byte to int, instead of byte we
can replace int(before a+b), it will excuite succesfully
| Is This Answer Correct ? | 1 Yes | 0 No |
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