9*9 1:4:8 ratio using how to calculate the material for
40mm aggregate ,cement &sand please tell me answer
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Answer Posted / sravan875
1:4:8 Ratio means 1%cement,4%aggregate,8%sand.
cement percentage--1/13=0.0769231cum.
aggregate %---4*0.0769...=0.3076924cum.
Sand % ----8*0.0169...=0.6153848cum..
Cement=0.0769*2370kg/cum (unit weight of concrete)=182.30775kg
40mm Aggregate=(density 1950kg/cum).
aggregate needed=0.3076924*1950=600.00kg of aggregate
Sand density(dry,packed)---1600-1900kg/cum
sand(dry,packed)-0.6153848*1750=1076.9234 Kg of sand is required.
Cement=182.3 Kgs
Aggregate=600Kgs
Sand=1077 Kgs
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