there are two candidates p and q in an election.During the
campaign,40% of the voters promised to vote for P ,and rest
for Q.however, on the day of election 15% of the voter went
back on their promise to vote for P and instead voted for Q.
25% of the voters went back on their promise to vote for Q
and instead voted for P.suppose,P lost by two votes,then
what was the total no. of voters.
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Answer Posted / rajmannar naidu
Let the number of voters be 100.
Then, the number of candidates which promised to vote for P = 40
and the no. of candidates promised to vote for Q = 100 – 40 = 60
According to question,
15% of 40 = 6 voters went back on their promise to vote for
P and instead voted for Q.
and 25% of 60 = 15 voters went back on their promise to vote
for Q and instead voted for P.
∴ Number of Votes for P = 40 – 6 + 15 = 49
and Number of Votes for Q = 60 + 6 – 15 = 51
Difference of Votes = 51 – 49 = 2.
Also P lost by 2 Votes.
⇒ Number of Voters were 100.
| Is This Answer Correct ? | 36 Yes | 2 No |
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