how much quantity are required like cement,sand,aggregate
for (46*29*0.41)feet slab? how much this quantity can be
calculated?
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Answer Posted / asad ali
wet volume conc: = 546.94 cu.ft
lets supposed ratio of conc: = (1:2:4)
sum of ratio = 7
first we find dry volume according to nature
dry volume of con: = 546.94*1.54 = 842.287cu.ft
1.54 is constant for conc: and 1.27 is constant for mortar
after a that we find cement,sanda and crush quantity OK
quantity of cement = ratio of cement *dry volume
--------------------------------
sum of ratio
this is the formula OK
= 1*842.287/7
=120.32 cu.ft OK
in bags of cement
we know that one bag of cement = 1.25cu.ft
so there fore 120.32/1.25 = 96.26 bags
say 96.5 bags
quantity of sand = ratio of sand * dry volume / sum of ratio
= 2*842.287 = 240.65cu.ft
quantity of crush = ratio*dry volume / sum of ratio
= 4*842.287/7
= 481.306cu.ft OK
quantity of cement = 96.5 bags
quantity of sand = 240.65 cu.ft
and last one
quantity of crush = 481.306 cu.ft
OK OK Ok Ok Ok any Question about contact me
civil.com7875@yahoo.com
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