Answer Posted / sreenatha

let the binary tree be not symmetric , then it has n-1 edges
excluding the edges from deficient nodes(nodes that have
atmost one child) to NULL.
Suppose , the binary tree was perfectly symmetric (i.e,
every node including the root has exactly two children).
Then , the total no.of edges including the edges from leaf
nodes to NULL would be 2 * N .
So , required ans = 2*N - N-1 = N+1

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