d/p flow transmitter LP side give to pressure.what you
geting out put ? how you get(ma)?
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Answer Posted / jazz
Dp transmitters work by measuring the difference between the
pressure measured on the high pressure port (HP) and the low
pressure port (LP). If for example the pressure on the HP is
100 psi and the pressure on the LP is 75 psi, the DP
transmitter will measure the difference of 25 psi. Let say
for example that the dp transmitter range is calibrated from
0 to 50 psi dp, the transmitter will output a proportional
12 mA (representing 50% of the dp range) The 24VDC supply on
serves to give power to the transmitter electronics so that
the transmitter will output a proportional 4-20mA signal
corresponding to the pressure difference sensed by the
pressure ports.
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Q1: Consider part of a control loop, which excludes the transmitter, consisting of a process, a controller and a control valve which may be represented by two dead times of 0.5 min each and three exponential lags of 0.8 min., 1.0 min. and 1.5 min. respectively. We wish to express this system as an overall first order plus dead time (FOPLD) model ie gain, time constant and process dead time. (We will see later that this is often done, to simplify controller tuning). For this exercise, gain is considered to be 1.0. (A) If the transmitter is a flow transmitter whose behaviour can be described by a dead time of 0.2 min. and an exponential lag of 0.5 min. in terms of the overall dead time and overall first order lag how can the system behaviour be approximated ? Overall dead time = Overall time constant = (B) If the transmitter is a temperature transmitter with a temperature sensor in a protecting well whose behaviour can be described by a dead time of 0.7 min. and an exponential lag of 15 min. how can the overall system behaviour be approximated now? Overall dead time = Overall time constant =
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