Two candles of equal lengths and of different thickness are
there. The thicker one will last of six hours. The thinner
2 hours less than the thicker one. Ramesh light the two
candles at the same time. When he went to bed he saw the
thicker one is twice the length of the thinner one. For how
long did Ramesh lit two candles ?please describe full
description
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Answer Posted / rajesh
Both are Equal length: L
Thick's burning rate: L/6
Thin's burning rate: L/4
After X hours (at bed time) of burning, remaining lengths:
Thick: L-(LX/6) and Thin: L-(LX/4)
But, at X hours, thick is twice as long as thin. i.e.:
L-(LX/6)=2[L-(LX/4)]
1-(X/6)=2-(X/2)
Solve for X and get 3.
| Is This Answer Correct ? | 139 Yes | 7 No |
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