#include<stdio.h>
#include<conio.h>
# define swap(a,b) temp=a; a=b; b=temp;
void main( )
{
int i, j, temp;
i=5;
j=10;
temp=0;
if( i > j)
swap( i, j );
printf( "%d %d %d", i, j, temp);
}
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Answer Posted / manish soni tagore collage jai
my dear frd....
here some hapen.
#define swap(a,b) temp=a;a=b;b=temp;----------(1)
is was as function of swap two no;(but it is differnt frm
funtion.)
so
at i>j;
enter swap(i,j);
so jump at eq(n) ---(1) and call swap function'
and
temp=5;
i=10;
j=0;
you see three variable.
but it printf i,j to convert swap.
bcoz it have two arguments.
and print temp=0;
becoz temp have 0;
| Is This Answer Correct ? | 0 Yes | 7 No |
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