| Question |
what"s the formula to find the quantity (consumption) of
cement,sand,aggregate for 1m3(1:2:4)? |
|
Question Asked At :: L&T, Isher, L, ABB, ABB, Spectra, Saudi Oger, Just Information, Strati |
|
Question Submitted By :: shaunpaulstar |
|
I also faced this Question!! |
Rank |
Answer Posted By |
| |
Answer
|
Ratio=1:2:4(cement:fine
agg.:coarse agg.)
Sum of the ratio=1+2+4=7.
Total dry mortar for 1cum
cement conc.=1.54(it is fixed)
There for=1.54/7=.22cum
Then quantiy of,cement=.22 into
28.8=6.24 bags.
Sand=.22 into 2(ratio of
sand)=.44cu m.
Aggregate(shingle or bajri)=.22
into 4=.88 cu m.
Materialr for 1cum cement conc.
1:2:4.
Cement=6.24bags
Sand= 0.44cum
Agg.=0.88cum
|
|
Vishal Rana
|
| |
| View All Answers |
| |
|
To Refer this Site to Your Friends 
Site Map
