main()
{
int x=20,y=35;
x = y++ + x++;
y = ++y + ++x;
printf("%d %d\n",x,y);
}
what is the output?
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Answer Posted / sagar
here first in x = y++ + x++;
= (35+1) + (20+1);//here value of x is not
= 36 + 21; assigned to 21 as x++
= 57... and 'lly to y++....
now the value of x = 57.
now for y = ++y + ++x;
= (1+35) + (1+57);
= 36 + 58;
= 94...
therefore,after performing all operatioins we get,
x==57 And y==94....
| Is This Answer Correct ? | 6 Yes | 4 No |
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